0 votes

Hi,
I have this code:

extends KinematicBody


var path = []
var path_node = 0
var speed = 20


onready var navigator = get_parent()
onready var player = get_parent().get_node("Player")


func _physics_process(delta):
if path_node < path.size():
    var direction = (path[path_node] - global_transform.origin)
    if direction.length() < 1:
        path_node += 1
    else:
        move_and_slide(direction.normalized() * speed, Vector3.UP)


func move_to(target_pos):
path = navigator.get_simple_path(global_transform.origin, target_pos)
path_node = 0


func _on_Timer_timeout():
print("Timeout")
move_to(player.global_transform.origin)

As you can see, the move_to function updates the path between the player and the enemy, and I call it when the timer timeouts, and if I call it in the _physics_process function, the enemy does not move to the player. How can I call that method from the _physics_process function without getting this bug.
Thanks in advanced.

Godot version 3.3.2
in Engine by (115 points)

Hi.
so the code above works? But if you put "moveto(player.globaltransform.origin)" into the "physicsprocess()" function it dont work?

This is exactly that happening.

There's no underlying reason why you shouldn't be able to call functions within _physics_process.

If you comment out the other stuff and put a print command in your function, and then call it from _physics_process...
Does it print?

can you show us the version wich dont work? Maybe the error lies inside the way (or where) you call it?

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