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Attention | Topic was automatically imported from the old Question2Answer platform. |
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Asked By | bgegg |
insert function for insert.
can i replace list array like this?
i want replace value of 3 and 4 index as mino.
[1,0,0,2,2,0,0,1]
this is code.
extends Node2D
var list = [1,0,0,0,0,0,0,1]
var mino = [2,2]
func _ready():
var sl = list.slice(2,3)
list.insert(3,sl)
print(list)
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Reply From: | jgodfrey |
If I understand the question, it’d take a number of steps to do what you want. Though, it’d be easy to wrap up in a function.
You could do this a number of ways, but here’s one possibility:
func _ready()
var target = [0, 1, 2, 3, 4, 5]
var new = [5, 6]
print(target)
array_replace(target, new, 2)
print(target)
func array_replace(array_target, array_new, index):
for item in array_new:
array_target[index] = item
index += 1
Output:
[0, 1, 2, 3, 4, 5]
[0, 1, 5, 6, 4, 5]
Note, there’s no error checking in the above function. Things like array bounds checking should probably be incorporated…
thanks for comment.
i can understand your code in now.
bgegg | 2020-11-15 06:38