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Asked By | Firty |
var a:Int = 1
var b:Array = [0,0,0]
for x in b:
x = a
expectation: b = [1,1,1]
reality: b = [0,0,0]
I have the impression that I already managed to do something similar that worked. in these cases I always have to use something like this:
var a:Int = 1
var b:Array = [0,0,0]
for x in range(b.size()):
b[x] = a
I’m forgetting something? Or is it not possible to change b by manipulating the x as I did in the first example?
afaik it’s not possible to change the iterator reference directly.
Magso | 2020-10-30 19:08