Function for

Question

var a:Int = 1
var b:Array = [0,0,0]
for x in b:
  x = a

expectation: b = [1,1,1]
reality: b = [0,0,0]

I have the impression that I already managed to do something similar that worked. in these cases I always have to use something like this:

var a:Int = 1
var b:Array = [0,0,0]
for x in range(b.size()):
  b[x] = a

I'm forgetting something? Or is it not possible to change b by manipulating the x as I did in the first example?

Comments

afaik it's not possible to change the iterator reference directly.