0 votes

What is $'.'?
If I have a code like:


onready var test = $'.'

function _ready():

I get an output in the debugger as
[Node2D: 1207]

What does this mean?

in Engine by (100 points)

1 Answer

+1 vote

$ is a shortcut for get_node(). get_node() will get the node at the provided path. get_node('.') or $'.' would get the current node, because . represents the current node. You can read the docs for it here.

by (68 points)

Thanks for explaining.

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