Convert PoolByteArray to float

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:information_source: Attention Topic was automatically imported from the old Question2Answer platform.
:bust_in_silhouette: Asked By programagor

My code currently calculates the single-precision float manually based on the IEEE 754 specs. However, in languages like C, this entire casting operation is effectively a nop. Is there a better (faster) way to do this conversion?

func bin2float(pkt:PoolByteArray) -> float:
  #Convert packet to an array of bools
  var arr:Array=[]
  for byte in pkt:
      for _i in range(0,8):
          arr.append(byte%2)
          byte/=2
          
  #Extract sign
  var r_sign:int
  if arr[31]==1:
      r_sign=-1
  else:
      r_sign=1
  
  #Extract exponent
  var r_exp:int=0
  for i in range(30,22,-1):
      r_exp*=2
      r_exp+=arr[i]
  r_exp-=127
  
  #Extract mantissa
  var r_mant:float=0
  for i in range(0,23):
      r_mant+=arr[i]
      r_mant/=2
  r_mant+=1
  
  return r_sign*pow(2,r_exp)*r_mant

I tried using some of the Data Packet classes, but they seem to require an entire protocol setup to use.

2
:bust_in_silhouette: Reply From: klaas

Hi,
you can do it with the StreamPeerBuffer

var spb = StreamPeerBuffer.new()
spb.data_array = pkt
var single_float = spb.get_float()