How can I make a variable that was changed slowly go back to it's original value?

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:bust_in_silhouette: Asked By AcidPanda

How can I make a variable that was changed slowly go back to it’s original value?

I’m trying to find out how to slowly, over time, return a variable to it’s default value.
The default would be 0. if it was changed to -1, it would work it’s way back to 0; ( Same with positive 1)

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:bust_in_silhouette: Reply From: DDoop

Hopefully, the gist is clear:

const VARIABLE_DELTA # how much per frame to de-increment variable
const DEFAULT_VALUE = 0 # desired resting position of variable

func _process(delta):
    if variable > DEFAULT_VALUE: # can also use != or <, obviously
    reduce(variable, delta)  # but this is specific to greater than comparison
    ...

func reduce(_variable, delta):
    _variable -= VARIABLE_DELTA * delta # omitt delta if you don't need fps precision
    clamp(variable, DEFAULT_VALUE ) # don't let it get too small
...

func clamp(_variable, _default_value): # underscores because reusing variable names is scary
    if _variable < _default_value
    _variable = _default_value

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jgodfrey | 2020-07-30 20:53

Thanks, didn’t think you could highlight a block and then apply the formatting. I write the code for my answers in this editor and the code block doesn’t behave well when you write like that.

DDoop | 2020-07-30 21:28