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Asked By
lyji
extends Node
var dialogue = ["i am [i]extremely[/i] confused but that's ok",
var dialogueIndex := 0
var stringFinished := false
var textSpeed := .005
func _ready():
load_dialogue()
func _process(delta):
$"textIndicator".visible = stringFinished
if Input.is_action_just_pressed("ui_accept"):
load_dialogue()
func load_dialogue():
if dialogueIndex < dialogue.size():
$TextureRect.set_visible(true)
stringFinished = false
var temp := ""
var foundBold = -1
var boldDone = false
$dialogueText.clear()
$dialogueText.set_visible(true)
$charText.set_visible(true)
var t = Timer.new()
t.set_wait_time(textSpeed)
t.set_one_shot(true)
for letter in dialogue[dialogueIndex]:
temp = dialogue[dialogueIndex]
var findBold = temp.find("[i]")
var findEndBold = temp.find("[/i]")
var restOfSentence = ""
if (temp.find("[i]") != -1) and (boldDone == false):
stringFinished = false
var beginning = temp.substr(0, findBold)
var boldedEnd
if findEndBold != -1:
restOfSentence = temp.substr(findEndBold+4, temp.length())
boldedEnd = temp.substr(findBold+3, findEndBold)
elif findEndBold == -1:
boldedEnd = temp.substr(findBold+3, temp.length())
$dialogueText.set_bbcode("")
for letter in beginning:
t.start()
$dialogueText.append_bbcode(letter)
yield(t, "timeout")
boldDone = true
for letter in boldedEnd:
t.start()
$dialogueText.append_bbcode("[i]" + letter + "[/i]")
yield(t, "timeout")
boldDone = true
for letter in restOfSentence:
t.start()
$dialogueText.append_bbcode(letter)
yield(t, "timeout")
boldDone = true
$dialogueText.append_bbcode(beginning + "\n" + boldedEnd + "\n" + restOfSentence)
stringFinished = true
elif stringFinished == false:
for letter in temp:
t.start()
$dialogueText.append_bbcode(letter)
yield(t, "timeout")
stringFinished = true
else:
queue_free()
dialogueIndex += 1
I would have used a tween function, but I wanted to add sound effects for each letter displayed. This probably isn’t the most efficient way to do it, but I wanted to get some practice in anyways.
I thought that for example:
a _ [ i ] w o r d [ / i ] .
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
Would print something like “a word.” if I called word.substr(2,14). When I run the code it gives me the correct beginning and end but not middle.
I know it says bold in the variables, but I was just testing italics lol. Thanks in advance!
extends Node
"""
match [textSpeedInput]:
[immediate]
immediateText = 0
[slow]
textSpeed = .025
_
textSpeed = .005
"""
var dialogue = ["yi er san si", "wu [b]liu![/b] qi", "wo [b]de pong yo[/b]u", "[b]zai na li"]
var dialogueIndex := 0
var stringFinished := false
var textSpeed := .005
var boldDone = false
#":" makes it so that it will never change the variable type
func _ready():
load_dialogue()
#When ready, call on the load_dialogue() func and
#display text inside the dialogue array
func _process(delta):
$"textIndicator".visible = stringFinished
#Doesn't need a .play() because it is set to
#"Autoplay on Load" already
if Input.is_action_just_pressed("ui_accept") and stringFinished and boldDone:
load_dialogue()
func load_dialogue():
if dialogueIndex < dialogue.size():
$TextureRect.set_visible(true)
stringFinished = false
var temp := ""
var foundBold = -1
boldDone = false
$dialogueText.clear()
$dialogueText.set_visible(true)
$charText.set_visible(true)
var t = Timer.new()
t.set_wait_time(textSpeed)
t.set_one_shot(true)
self.add_child(t)
for letter in dialogue[dialogueIndex]:
temp = dialogue[dialogueIndex]
var findBold = temp.find("[b]")
var findEndBold = temp.find("[/b]")
var restOfSentence = ""
if (findBold != -1) and (boldDone == false) :
stringFinished = false
var beginning = temp.substr(0, findBold)
var boldedEnd
var endCalc = (temp.substr(findEndBold, temp.length())).length()
var frontCalc = (temp.substr(0, findBold+3)).length()
var midLenCalc = abs(temp.length()-endCalc-frontCalc)
#Len, not index
if findEndBold != -1:
restOfSentence = temp.substr(findEndBold+4, temp.length())
#boldedEnd = temp.substr(findBold+3, endCalc-3)
boldedEnd = temp.substr(findBold+3, midLenCalc)
#Second parameter takes how many letters you want to continue for!!
#Not the index, but still need to add one
$dialogueText.set_bbcode(str("temp.length()" + str(temp.length()) + " - endCalc " + str(endCalc) + " - frontCalc" + str(frontCalc) + " = midLenCalc" + str(midLenCalc) + "\n"))
elif findEndBold == -1:
boldedEnd = temp.substr(findBold+3, temp.length())
#$dialogueText.set_bbcode("")
for letter in beginning:
t.start()
$dialogueText.append_bbcode(letter)
yield(t, "timeout")
boldDone = true
for letter in boldedEnd:
t.start()
$dialogueText.append_bbcode("[b]" + letter + "[/b]")
yield(t, "timeout")
boldDone = true
for letter in restOfSentence:
t.start()
$dialogueText.append_bbcode(letter)
yield(t, "timeout")
boldDone = true
$dialogueText.append_bbcode("\n" + beginning + "\n" + boldedEnd + "\n" + restOfSentence)
stringFinished = true
elif stringFinished == false:
for letter in temp:
t.start()
$dialogueText.append_bbcode(letter)
yield(t, "timeout")
stringFinished = true
boldDone = true
else:
queue_free()
#Once the load_dialogue function is broken because
#it read the entire array, the queue will be
#freed and nothing will show up on screen
dialogueIndex += 1
Figured it out. I’ll just dump my code here in case anyone else had the same issue. I’ve been coding in Java for months so I forgot how to use substrings in Godot oops. Once I figured out the length instead of the index it worked.
dude you’re seriously a life saver lmao, I stared at my code for hours wondering why it wasn’t working lol
