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Attention | Topic was automatically imported from the old Question2Answer platform. |
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Asked By | Felipe |
When I am initialising a script, what is the call order of this:
_ready(),
onready var,
const,
var,
export var
?
All of this are in the same script. Ignoring the fact that may or not have a child node.
Thank you!
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Reply From: | njamster |
What do you mean? Variables and constants aren’t called, so there isn’t a call order either. All of them will be available when _ready is called.
which one is called first onready var or ready
supper_raptor | 2020-05-20 07:42
onready var. It’s easy to check for yourself:
onready var variable = "test"
func _init():
print("INIT: ", variable)
func _ready():
print("READY: ", variable)
njamster | 2020-05-20 08:39
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Reply From: | Ertain |
From what I can tell, onready var is called when the node to which it is referring is instantiated, and it enters the node tree. The export var code is a bit trickier. If the user doesn’t have any value assigned to the exported variable in an _init() function, and the node isn’t being instanced, then it’ll receive the initial value defined in the script. So it may go something like this:
(export var) -> (onready var) -> ( _ready() ) -> (var/const, depending on which one was called first in the script)
For more information, look on the Godot Notifications article for more details.