Wait()-like function?!

Question

So, is there a built-in function to GDScript where I can pause a process in a script for a few seconds, say:

set_visible(false)
wait(1) #waits for 1 second
set_visible(true) #then continues the rest of the script after the 1 second wait

Answer 1

Try:

var t = Timer.new()
t.set_wait_time(3)
t.set_one_shot(true)
self.add_child(t)
t.start()
yield(t, "timeout")

Comments

Don't forget to free the timer afterwards, or you'll cause a memory leak.

t.queue_free()

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this works, but i tried to turn it into a function which didn't
anyone knows why?

func wait(s):
var t = Timer.new()
t.setwaittime(s)
t.setoneshot(true)
self.addchild(t)
t.start()
yield(t, "timeout")
t.queuefree()

func _ready():
hide()
wait(4)
show()

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Weirdly enough, when I did this in it's own function, it didn't work, but when I had the exact same code on the place where I called the wait function, it worked.

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This is not the best answer, since Godot has it's own dedicated function for this use-case: create_timer
(which is already mentioned in the comment below

So if you Googled this issue and ended up on this thread, check the create_timer function and yield-ing it instead of creating your own Timer

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create_timer

is not a better idea. It can work in some cases, but if the object that creates the timer is freed, the game will crash. In general it's best to avoid using yields until Godot 4.0, as I believe they fixed the issue.

Answer 2

See OS.delay_msec and OS.delay_usec.

Comments

Note that if you use those in the main thread, those will cause the project to freeze until the delay has expired.

Answer 3

yield(get_tree().create_timer(1.0), "timeout")

Comments

Does the timer created here get disposed?

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I believe that, once the routine has been resumed, the SceneTreeTimer object, returned by the create_timer () function, becomes invalid, as documented at:
https://docs.godotengine.org/en/3.0/getting_started/scripting/gdscript/gdscript_basics.html?highlight=yield#coroutines-with-yield