How to get the node that called the function?

+2 votes

There is a way?

in Engine by (692 points)

2 Answers

+2 votes
Best answer

You can't get the caller of a function, there is no point doing that. If you really need to, just pass it as an argument, like so:

First node:

node.the_function(self)

Second node:

func the_function(caller):
    print("Called by ", caller)
by (29,090 points)
selected by
+2 votes

If you don't actually need the node, but only a trace to the caller, you can also use get_stack() to get an array of the whole stack, index 0 being the innermost function. From the docs:

Array get_stack( )

Returns an array of dictionaries representing the current call stack.

func _ready():
    foo()

func foo():
    bar()

func bar():
    print(get_stack())

would print

[{function:bar, line:12, source:res://script.gd}, {function:foo, line:9, source:res://script.gd}, {function:_ready, line:6, source:res://script.gd}]
by (34 points)
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