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Asked By
LockManipulator
It seems that I can’t do
var array1 = []
if (xcoord, ycoord) not in array1:
#do something
or
for i in range(array1.size()):
if array1[i] == (xcoord, ycoord):
#do something
where xcoord and ycoord would be just random numbers. It keeps saying “Expected ‘)’ in expression” on the if statement line after xcoord. How can I check if this set of coordinates is in the array? The array will hold around 50 items.
Your not is at the wrong place: It must be written right after the if. And it should be [xcoord, ycoord] instead of (xcoord, ycoord) (with thanks @hilfazer):
var array1 = []
if not [xcoord, ycoord] in array1:
#do something
Just a little addition: If the xcoord and ycoord values are components of a vector you can write it like that:
var vector_array = [vector1, vector2, vector3, ...]
var vector = Vector2(xcoord, ycoord)
if not vector in vector_array:
#do something
It still doesn’t work,
if not (xcoord, ycoord) in array1:
is still saying “Expected ‘)’ in expression”. And I don’t understand what’s happening with the Vector2 code you put. What is vector1, vector2, etc?
LockManipulator | 2018-02-20 17:15
You need [], not () around your coords if your array contains 2-element arrays.
If it contains Vector2s, use this: Vector2(xcoord, ycoord)
hilfazer | 2018-02-20 17:34
Ah ok thanks!
LockManipulator | 2018-02-20 18:03
Thanks for your fast response to my mistake. I edited my answer accordingly.
